0.0295t^2-0.466t+1.75=0

Solution for 0.0295t^2-0.466t+1.75=0 equation:

0.0295t^2-0.466t+1.75=0

a = 0.0295; b = -0.466; c = +1.75;
Δ = b2-4ac
Δ = -0.4662-4·0.0295·1.75
Δ = 0.010656
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-0.466)-\sqrt{0.010656}}{2*0.0295}=\frac{0.466-\sqrt{0.010656}}{0.059}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-0.466)+\sqrt{0.010656}}{2*0.0295}=\frac{0.466+\sqrt{0.010656}}{0.059}
$